point-slope form

kasey

New member
Joined
Apr 2, 2006
Messages
3
I asked this in a previous post and I got the answers needed to set up my problem but I'm a little lost after my last step.

It was:
Write the point-slope form of an equation for the line passing through the point at (3,-6) with slope -4/3

I set the problem up like this:
y-y1 = m (x-x1)
y + 6 = m (x-3)
y+6=-4/3 (x-3)

eh. stupid fractions. i'm stuck.
a little push in the right direction?
 
In this case, I believe a push in the right direction would be a Stop Sign.

You're done. That is the Point-Slope Form. What else is needed?
 
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