Point slope vs intercept

[Audentes]

Am I correct In saying that point slope isolates x so x=the equation and slope intercept isolates y so y=equation?

 

[skeeter]

I wouldn’t say point-slope isolates x, although it can be done for either form

[MATH]y-y_1 = m(x-x_1) \implies y = m(x-x_1)+y_1[/MATH]
one step to isolate y ...

 

[Audentes]

I wouldn’t say point-slope isolates x, although it can be done for either form

[MATH]y-y_1 = m(x-x_1) \implies y = m(x-x_2)+y_1[/MATH]
one step to isolate y ...

Okay thank you

 

[JOwen56]

For slope-intercept form, y is isolated, so you are correct there. ( y = mx + b )
For point slope ( y−y1=m(x−x1) ), x is not isolated.

 

[Audentes]

For slope-intercept form, y is isolated, so you are correct there. ( y = mx + b )
For point slope ( y−y1=m(x−x1) ), x is not isolated.

Okay thank you, that clears it up more

 

[wishizuk]

I would state it this way:

"Slope-intercept form is a special case of point-slope Form."

By point-slope form, y - b = m(x - 0), which simplifies to y = mx + b.

 

[Audentes]

I would state it this way:

"Slope-intercept form is a special case of point-slope Form."

By point-slope form, y - b = m(x - 0), which simplifies to y = mx + b.

ok thank You

 

[wishizuk]

You are welcome!