P petrol.veem New member Joined Oct 2, 2007 Messages 29 Oct 16, 2007 #1 How does one convert the following into polar co-ordinates and then take the limit as (x,y)-->(0,0)? f(x,y) = [sin(x^2 + y^2)] / [x^2 + y^2]
How does one convert the following into polar co-ordinates and then take the limit as (x,y)-->(0,0)? f(x,y) = [sin(x^2 + y^2)] / [x^2 + y^2]
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Oct 16, 2007 #2 What basic polar-coordinate identity do you have for x<sup>2</sup> + y<sup>2</sup>? :wink: Eliz.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Oct 17, 2007 #3 If you make the appropriate substitution for x^2+y^2, then you will have a well-known limit.
P petrol.veem New member Joined Oct 2, 2007 Messages 29 Oct 17, 2007 #4 ok, i see the how the polar co-ordinate one solves now. the second part of the question asks to solve the limit using the epsilon-delta approach. I am having trouble getting started. any ideas?
ok, i see the how the polar co-ordinate one solves now. the second part of the question asks to solve the limit using the epsilon-delta approach. I am having trouble getting started. any ideas?
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Oct 17, 2007 #5 How about using the "well-known limit" from Calc I, mentioned previously? Eliz.