The polynomial 4x^3 + ax + 2, where a is a constant, is denoted by p(x). It is given that 2x + 1 is a factor of p(x).
(i) Find the value of a.
(ii) When a has this value
(a) factorise p(x)
(b) solve inequality p(x)> 0, justifying your answer
Answer:
I found the value of a equal to 3 by using the factor theorem.
Then I factorised p(x) by dividing p(x) by 2x+1 and got quotient 2x^2-x+2.
so p(x) = (2x+1) (2x^2-x+2)
I was not able to do number b . I don't really know what it is trying to say.
(i) Find the value of a.
(ii) When a has this value
(a) factorise p(x)
(b) solve inequality p(x)> 0, justifying your answer
Answer:
I found the value of a equal to 3 by using the factor theorem.
Then I factorised p(x) by dividing p(x) by 2x+1 and got quotient 2x^2-x+2.
so p(x) = (2x+1) (2x^2-x+2)
I was not able to do number b . I don't really know what it is trying to say.