polynomials

[The_Guy_Who_Needs_Help]

i got an answer but dont know if its right.if my solution is 10r[2r(2r-3)-3(2r-3)]then that will factor to 10r(2r-3) to the third right?

 

[lookagain]

i got an answer but dont know if its right.if my solution is 10r[2r(2r-3)-3(2r-3)]
then that will factor to 10r(2r-3) to the third right?

No.

2r(2r - 3) -3(2r - 3) =

(2r - 3)(2r - 3)


So the original expression is equal to


\(\displaystyle 10r(2r - 3)(2r - 3) = \)


\(\displaystyle 10r(2r - 3)^2\)

 

[lookagain]

Firstly we will solve the plynomial in the bracket :-
[2r(2r-3)-3(2r-3)]
= 2r(2r - 3) -3(2r - 3)
= (2r - 3)(2r - 3)
So now 10r(2r-3)^2
\(\displaystyle > > \)Now you can solve polynomial.\(\displaystyle < < \)

amit28it,

I stopped with my answer on purpose
(but which I may have shown too many steps for the student).

However, there is no "solving the polynomial," because the OP didn't mention
that polynomial as being part of an equation.