pre-algebra money problem

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A bank tellers supply of dimes and nickles totals $3.60. If the tellers supply of dimes numbers one more than three times the number of nickles, how many dimes are there?
 
>A bank tellers supply of dimes and nickles totals $3.60. If the tellers supply of dimes numbers one more than three times the number of nickles, how many dimes are there?

It would help if we knew whether you can use two variables or only one.

You need to name things. In problems such as this it is important to recognize the difference between the number of coins and the value of them. Also, you need to be consistent in whether you set it up in dollars or in cents. If you choose dollars, you will have decimals.

Let's let d represent the number of dimes and n represent the number of nickels.

The equation can be >>> the value of the nickels plus the value of the dimes equals the total value.

The problem states " If the tellers supply of dimes numbers one more than three times the number of nickels". This tells you that d=3n+1.

The value of the nickels will be .05n or 5n depending on whether you want to set it up in terms of dollars or cents.
So, the value of the dimes will be .10(3n+1) or 10(3n+1)

Now, can you put this all together and solve?

Can you put this all together and come up with the solutions?
 
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