Irv counted 57 helmets and 115 wheels parked in the front of the store. He knows he has an equal number of unicycles and tandem bikes. He also knows that he has 32 regular bikes. every cycle has a helmet for each rider. How many unicycles, tandem bikes, and tricycles does Irv have?
pre-algebra
- Thread starter bb1125
- Start date
1(x) for unicycle
2(x) for tandems
3(x) for tricycles
2(32) for regular bikes if im thinking wheels which is 6(x) + 64 = 115, subtracting 64 wheels from both sides leaving 51.
6(x) = 51, dividing both sides by 6 I have 8 3/6 or 8 1/2
1(8) + 2(8) + 3(8) + 64 = 112????
1(9) + 2(9) + 3(9) + 64 = 118????
Thinking
1(x) for unicycles
2(x) for tandems
1(x) for tricycles if im thinking helments which is 4(x) = 57. i need to subtract 32 helments for regular bikes which leaves 25
4(x) = 25, dividing both sides by 4 I have 6 1/4.
1(6) + 2(6) + 1(6) = 25
24 does not equal 25.
1(7) + 2(7) + 1(7) = 25
28 does not equal 25
basically I know the logic but am having trouble with equations. I know unicycles and tandems need to be the same. by substitution Im either over three or under three. who gets the three?
2(x) for tandems
3(x) for tricycles
2(32) for regular bikes if im thinking wheels which is 6(x) + 64 = 115, subtracting 64 wheels from both sides leaving 51.
6(x) = 51, dividing both sides by 6 I have 8 3/6 or 8 1/2
1(8) + 2(8) + 3(8) + 64 = 112????
1(9) + 2(9) + 3(9) + 64 = 118????
Thinking
1(x) for unicycles
2(x) for tandems
1(x) for tricycles if im thinking helments which is 4(x) = 57. i need to subtract 32 helments for regular bikes which leaves 25
4(x) = 25, dividing both sides by 4 I have 6 1/4.
1(6) + 2(6) + 1(6) = 25
24 does not equal 25.
1(7) + 2(7) + 1(7) = 25
28 does not equal 25
basically I know the logic but am having trouble with equations. I know unicycles and tandems need to be the same. by substitution Im either over three or under three. who gets the three?
Remove the 32 regulars: so we have 25 helmets and 51 wheels to account for.
4 unicycles : 4 helmets and 4 wheels
4 tandems : 8 helmets and 8 wheels
13 tricyces: 13 helmets and 39 wheels
==================================
Total......: 25 helmets and 51 wheels
Can you get some sleep now :wink:
4 unicycles : 4 helmets and 4 wheels
4 tandems : 8 helmets and 8 wheels
13 tricyces: 13 helmets and 39 wheels
==================================
Total......: 25 helmets and 51 wheels
Can you get some sleep now :wink:
4 unicycles : 4 helmets and 4 wheels
4 tandems : 8 helmets and 8 wheels
13 tricyces: 13 helmets and 39 wheels
==================================
Total......: 25 helmets and 51 wheels
A = unicycles + tandems : so A =3 helmets, 3 wheels
B = tricycles
3A + B = 25
3A + 3B = 51
Subtract:
0 + 2B = 26
B = 13
4 tandems : 8 helmets and 8 wheels
13 tricyces: 13 helmets and 39 wheels
==================================
Total......: 25 helmets and 51 wheels
A = unicycles + tandems : so A =3 helmets, 3 wheels
B = tricycles
3A + B = 25
3A + 3B = 51
Subtract:
0 + 2B = 26
B = 13
