J jasmine t New member Joined Jun 3, 2011 Messages 1 Jun 3, 2011 #1 use Gaussian elimination to solve the system of equations. 1/2x-y+z-w=1 -x+y+z+2w=-3 x-z=-2 y+w=0
D Denis Senior Member Joined Feb 17, 2004 Messages 1,700 Jun 3, 2011 #2 Can't see your work...so can't tell where you're stuck... Can you solve this simple one: x + y = 20 x - y = 4
Can't see your work...so can't tell where you're stuck... Can you solve this simple one: x + y = 20 x - y = 4
D Deleted member 4993 Guest Jun 3, 2011 #3 jasmine t said: use Gaussian elimination to solve the system of equations. 1/2x-y+z-w=1<<< Is that supposed to be<< \(\displaystyle \frac{1}{2x-y+z-w} \ = \ 1\) -x+y+z+2w=-3 x-z=-2 y+w=0 Click to expand... Your first equation looks like: \(\displaystyle \frac{1}{2x} - y + z - w} \ = \ 1\) if it was supposed to like: \(\displaystyle \frac{1}{2x-y+z-w} \ = \ 1\) you should have written: 1/(2x-y+z-w)=1 ................ using parenthesis as grouping symbol. Please fix your post (if needed) and Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
jasmine t said: use Gaussian elimination to solve the system of equations. 1/2x-y+z-w=1<<< Is that supposed to be<< \(\displaystyle \frac{1}{2x-y+z-w} \ = \ 1\) -x+y+z+2w=-3 x-z=-2 y+w=0 Click to expand... Your first equation looks like: \(\displaystyle \frac{1}{2x} - y + z - w} \ = \ 1\) if it was supposed to like: \(\displaystyle \frac{1}{2x-y+z-w} \ = \ 1\) you should have written: 1/(2x-y+z-w)=1 ................ using parenthesis as grouping symbol. Please fix your post (if needed) and Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
