Precise Def of Limit

ku1005

Junior Member
Joined
Oct 27, 2006
Messages
71
Hey guys, im new to this topic and just wodering how my lecturer got the folowing, as he said it was easy to do ourselves??

(e=epsilon)


"show that the limit x-> (infinite) of (x^2-1)/(x^2+1)=1"

specifically, he just comes right out and says let K = sqrt(2/e) and let x>K

impling 2/x^2 < e etc etc

I understand that letting K = above, means the equation ends up nicely becoming less then epsilon, however, what is the systematic approach to solving this value????...ie so i can use it for other equations which it is not as obvious?...if a process exists that is...

i tried this

-e < ( x^2-1)/(x^2-1) - 1 < e

-e < -2/(x^2+1) < e

-e < 2/(x^2+1) < e

but then how can you say that 2/(x^2+1)<=2/x^2<e ?????this the part I dont get!!!


so any help would be gretaly appreciated!!!

cheers

rhys
 
x^2 + 1 >= x^2 so of course 1/(x^2 + 1) =< 1/(x^2).

Consider the stage where you have |2/(x^2 + 1)| < e. Then 2/(x^2) < e, or x^2 > 2/e so x < -sqrt(2/e) or x > sqrt(2/e). Thus an appropriate K>0 would be sqrt(2/e).

This is the systematic approach, if you like.
 
Top