#### williamrobertsuk

##### New member

- Joined
- May 18, 2019

- Messages
- 32

- Thread starter williamrobertsuk
- Start date

- Joined
- May 18, 2019

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- Joined
- Jan 29, 2005

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\(\displaystyle \begin{array}{*{20}{c}}

H&H&H\\

H&H&T\\

H&T&H\\

H&T&T\\

T&H&H\\

T&H&T\\

T&T&H\\

T&T&T

\end{array}\)

Now

If you do not then do not expect any further help.

- Joined
- May 18, 2019

- Messages
- 32

Thanks, and I am new here, I started posting before I even read the rules, but I am working on it and I will write back!all the possible outcomes.

\(\displaystyle \begin{array}{*{20}{c}}

H&H&H\\

H&H&T\\

H&T&H\\

H&T&T\\

T&H&H\\

T&H&T\\

T&T&H\\

T&T&T

\end{array}\)

NowYOUdo some work. Answer each of the questions andpost the results.

If you do not then do not expect any further help.

- Joined
- May 18, 2019

- Messages
- 32

1. =0.125all the possible outcomes.

\(\displaystyle \begin{array}{*{20}{c}}

H&H&H\\

H&H&T\\

H&T&H\\

H&T&T\\

T&H&H\\

T&H&T\\

T&T&H\\

T&T&T

\end{array}\)

NowYOUdo some work. Answer each of the questions andpost the results.

If you do not then do not expect any further help.

2.=0.125

Now, the other two, I am still struggling, I thought it could be 0.25, but it ain't. Any help there?

- Joined
- May 18, 2019

- Messages
- 32

3.=0.37

4.=0.5

4.=0.5

- Joined
- Jan 29, 2005

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- 8,527

Correct

2.=0.125Correct

Now, the other two, I am still struggling, I thought it could be 0.25, but it ain't. Any help there?

- Joined
- May 18, 2019

- Messages
- 32

I managed to calculate 4 and 5, the answers are posted above! Thanks!

- Joined
- Jan 29, 2005

- Messages
- 8,527

3.=0.37Correct

4.=0.5Correct