Probabilities involving disjoint events

Have you tried anything?

I would first try using De Morgan's laws to simplify [MATH]A\cup(B^c\cap C^c)^c[/MATH]. Then question 1 will be fairly easy.

Please show us your work, and ask any specific questions it raises. Also, please reread the submission guidelines.
 
Find the problem attached! :)

View attachment 12190
Here are HINTS only. You must apply them and post results.
For 1. (BcCc)c=BC\displaystyle {\left( {{B^c} \cup {C^c}} \right)^c} = B \cap C

For 2. If H & G\displaystyle H~\&~G are disjoint events then P(HG)=P(H)+P(G)\displaystyle \mathcal{P}(H\cup G)=\mathcal{P}(H)+\mathcal{P}(G)

For 3. (Ac(BcCc))c=A(BcCc)c\displaystyle {\left( {{A^c} \cap \left( {{B^c} \cup {C^c}} \right)} \right)^c} = A \cup {\left( {{B^c} \cup {C^c}} \right)^c}
 
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