probabilities, permutations, and combinations

Genisnotme

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Suppose you randomly choose a tetter in the alphabet from A to L. What are the odds against choosing a vowel?
 
Suppose you randomly choose a tetter in the alphabet from A to L. What are the odds against choosing a vowel?
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Please share your work/thoughts about this problem
 
Suppose you randomly choose a tetter in the alphabet from A to L. What are the odds against choosing a vowel?
How many vowels are there from a to l?
How many letters are there from a to l?
 
Hey, what kind of help site is this? I want an answer and an explanation that a monkey can follow, and I want them NOW. I don’t got to answer your stinking questions.
 
favorable outcomes divided by the number of possible outcomes.
you have 12 letters form A to L
A,b,c,d,e,f,g,h,i,j,k,l (these are all the possibilities you have)
but you want the vowels that are in this range of possible outcomes.
how many vowels you have in there?.
you have 3 vowels to choose in 12 possibilities.
these are your odds against choosing a vowel
3/12
pka just said it. you just had to do this little bit of thinking.
ps: of course, this is assuming you're talking about the English alphabet.
 
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Suppose you randomly choose a tetter in the alphabet from A to L. What are the odds against choosing a vowel?
favorable outcomes divided by the number of possible outcomes.
you have 12 letters form A to L
A,b,c,d,e,f,g,h,i,j,k,l (these are all the possibilities you have)
but you want the vowels that are in this range of possible outcomes.
how many vowels you have in there?.
you have 3 vowels to choose in 12 possibilities.
these are your odds against choosing a vowel
3/12
pka just said it. you just had to do this little bit of thinking.
ps: of course, this is assuming you're talking about the English alphabet.
Actually, no; pka's hints are (if taken directly) about a different question than was asked.

The "odds against" an event is the ratio "ways to fail":"ways to succeed". What you found is the probability of choosing a vowel, which is the fraction "ways to succeed"/"ways to try".
 
Actually, no; pka's hints are (if taken directly) about a different question than was asked.

The "odds against" an event is the ratio "ways to fail":"ways to succeed". What you found is the probability of choosing a vowel, which is the fraction "ways to succeed"/"ways to try".
Oh, thanks, Doctor Peterson. I thought it kind of strange because i have never seen a probability problem phrased that way, at least not those i have dealt with. Now it makes a lot of sense.
 
Oh, thanks, Doctor Peterson. I thought it kind of strange because i have never seen a probability problem phrased that way, at least not those i have dealt with. Now it makes a lot of sense.
What is the best to andwer this, if i can ask a question in a thread which is not mine.
 
How many vowels are there from a to l?= 3
How many letters are there from a to l?
=12

total number of outcomes on choosing a vowel =12
number of favorable outcomes=3
Number of unfavorable outcomes=12-3
9
odds in favor of choosing a vowel is 3 over 9.

odds against choosing a vowel
Odds = success/failures

Will favorable outcomes be considered 'successes'?.
 
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How many vowels are there from a to l?= 3
How many letters are there from a to l?
=12

total number of outcomes on choosing a vowel =12
number of favorable outcomes=3
Number of unfavorable outcomes=12-3
9
odds in favor of choosing a vowel is 3 over 9.

odds against choosing a vowel
Odds = success/failures

Will favorable outcomes be considered 'successes'?.
There are 3 vowels and 9 non-vowels, for a total of 12 letters. "Success" and "favorable" are the same thing. So:
  • Probability of choosing a vowel = success/total = 3/12 = 1/4
  • Odds in favor of choosing a vowel = success:failure = 3:9 = 1:3
  • Odds against choosing a vowel = failure:success = 9:3 = 3:1
Note that probability is a fraction (or decimal or percentage); odds are a ratio. We say "to", not "over".

Have you tried looking up the topic? Try here. Or here.
 
T
There are 3 vowels and 9 non-vowels, for a total of 12 letters. "Success" and "favorable" are the same thing. So:
  • Probability of choosing a vowel = success/total = 3/12 = 1/4
  • Odds in favor of choosing a vowel = success:failure = 3:9 = 1:3
  • Odds against choosing a vowel = failure:success = 9:3 = 3:1
Note that probability is a fraction (or decimal or percentage); odds are a ratio. We say "to", not "over".

Have you tried looking up the topic? Try here. Or here.
Thanks a million, Doc.!!. I will study it thoroughly!.
Excellent links!.
 
Is the poster paying attention to the answers given or he is busy on fb instagram..?
 
Hey, what kind of help site is this? I want an answer and an explanation that a monkey can follow, and I want them NOW. I don’t got to answer your stinking questions.
I would have loved to read the posts that were removed for you to make your post!
 
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