An urn contains 16 balls marked LOSE and 4 balls marked WIN.You and your friend take turns randomly picking a ball from the urn. The person who picks the fourth WIN ball wins the game. It does not matter who picked the first three WIN balls.
If your opponent draws first, what is the probability that you win? HINT: You could win on your second, third, fourth,..., or tenth draw but not on your first.
I have pretty much no idea how to go about this problem.
All I know is that it should be something along the lines of
the sum from k=2 to 10 for (insert some generalized formula)
Could someone explain this problem to me in terms of how to solve it and why you would solve it in such way?
Please and thank you!
If your opponent draws first, what is the probability that you win? HINT: You could win on your second, third, fourth,..., or tenth draw but not on your first.
I have pretty much no idea how to go about this problem.
All I know is that it should be something along the lines of
the sum from k=2 to 10 for (insert some generalized formula)
Could someone explain this problem to me in terms of how to solve it and why you would solve it in such way?
Please and thank you!