Qn: If a discrete random variable X has PGF GX(t) =e(0.12t+0.02t^2+0.07t^3 -0.21). What is the P(x=3)?
Now i know that GX(t) = summation ( tx . P(X=x)) and that Pk = p(x=k) which is the coefficient of tk in GX(t).
But in this case my PGF is an exponential. How should i go about it?
Now i know that GX(t) = summation ( tx . P(X=x)) and that Pk = p(x=k) which is the coefficient of tk in GX(t).
But in this case my PGF is an exponential. How should i go about it?