Probability problem

skhan

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Jul 15, 2019
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Bill has one of each of these cards (5 cards) : 1, 3, 5, 7 , 9
How many three digit numbers divisible by three can he make with his cards ?
 
Hint: A three digit number is divisible by 3 if the sum of the digits is divisible by 3.
 
Bill has one of each of these cards (5 cards) : 1, 3, 5, 7 , 9
How many three digit numbers divisible by three can he make with his cards ?
LOOK at reply #2. There are \(\displaystyle \binom{5}{3}=10\) sets of those three digits each of those sets can be arranged in six ways.
Consider the set \(\displaystyle \{1,3,5\}\) the sum of those three is nine which is dividable by three. So now we have six.
Can you finish?
 
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