There are 4 cards (ACE included) with pictures AND heart.From a standard pack of 52 cards, I draw 3 cards at random without replacement. What is the probability that all cards drawn are both hearts and picture cards?
is the answer: (3/52)*(2/51)*(1/50)?
If ACE is not included then - how many ways can you choose 3 cards from that group (Hearts and pictures) ? ------ 1 wayWhy would ace be included? I thought there are only 3 cards that are both heart and picture? (jack, queen and king)
Please kindly explain if I have gotten it wrong! Thank you.
I would agree with your first answer [imath]\left(\dfrac{3}{52}\right)\cdot\left(\dfrac{2}{51}\right)\cdot\left(\dfrac{1}{50}\right)[/imath].If ace is not included, then the probability is 1/22100. However, i am confused as to why there are 4 cards with pictures and heart?
Am I understanding the event incorrectly? I understood the event that “all three cards are both heart and picture” to be drawing “a jack, a queen and a king of hearts”, which is 1 out of 22100 ways.
Your wikipedia link states that names 'picture card' and 'face card' mean the same thing.It is extremely unusual to use picture card what standard English uses face cards.
Because a lot of card manufacturers draw a picture on each ace. However, the design on the aces do not show a person.confused as to why there are 4 cards with pictures and heart?