masonpbush
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- Nov 5, 2019
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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.964 g and a standard deviation of 0.296 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 33 cigarettes with a mean nicotine amount of 0.912 g.
Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 33 cigarettes with a mean of 0.912 g or less.
P(M < 0.912 g) = ?
Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 33 cigarettes with a mean of 0.912 g or less.
P(M < 0.912 g) = ?
Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.