Probability
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Please share your work/thoughts about this assignment
After having read what Subhotosh Khan asked you to read, let's deal with each question in a separate post. Let's devote this thread to #11.
[MATH]\text {P(A | B)} = \dfrac{\displaystyle \text {P(A and B)}}{\displaystyle \text {P(B)}}.[/MATH]
Have you ever seen that before? If so, what does it mean and what is its relevance to this problem?
[MATH]\text {P(A | B)} = \dfrac{\displaystyle \text {P(A and B)}}{\displaystyle \text {P(B)}}.[/MATH]
Have you ever seen that before? If so, what does it mean and what is its relevance to this problem?
pka
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- Jan 29, 2005
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\(\displaystyle
\begin{array}{*{20}{c}}
\text {habit}&\text{notcollege}&\text{college}&\text{totals} \\
\hline
\text {smoke}&{55}&{25}&{80} \\
\hline
\text{non - smoke}&{127}&{73}&{200} \\
\hline
\text{totals}&{182}&{98}&{280}
\end{array}\)
Using that table part a is \(\displaystyle \frac{98}{280}=0.35\)