Probability

[watchkimberly]

Can someone correct me if I am wrong?
At the end of each week, a generous teacher gives some candy to a few randomly selected students. There are 30 students in this teacher's class- 16 girls and 14 boys.
Question: To avoid appearing to favor one gender, the teacher will randomly choose 3 of the 16 girls and 3 of the 14 boys. How many possible groups of 6 can she choose?
My answer was 593,775 after doing 30P6/6!
My question is the next part, I'm not sure how to go about this:
To avoid appearing to favor one gender, the teach will randomly choose 3 of the 16 girls and 3 of the 14 boys. How many possible groups of 6 can she choose?
This is what I did: (16C3/3!)*(14C3/3!) = 203840, 203840/30*29*28*27*26*25/6! = 0.39010797 = 39.01

 

[Steven G]

1st question you posted: To avoid appearing to favor one gender, the teacher will randomly choose 3 of the 16 girls and 3 of the 14 boys. How many possible groups of 6 can she choose?

2nd question you posted: To avoid appearing to favor one gender, the teach will randomly choose 3 of the 16 girls and 3 of the 14 boys. How many possible groups of 6 can she choose?


They are the same question. Please update your post. Thanks.


You wrote: 0.39010797 = 39.01. Do you really believe that?

 

[watchkimberly]

At the end of each week, a generous teacher gives some candy to a few randomly selected students. There are 30 students in this teacher's class- 16 girls and 14 boys.
Question: If the teacher wanted to give candy to 6 of the students, how many possible groups of 6 students can she choose? My answer, 30C6/6! = 593,775
Question 2: To avoid appearing to favor one gender, the teach will randomly choose 3 of the 16 girls and 3 of the 14 boys. How many possible groups of 6 can she choose? My answer, (16C3/3!)*(14C3/3!) = 203840, 203840/30*29*28*27*26*25/6! = 0.39010797 = 39.01
Is this correct?

 

[Steven G]

Can you please list the 39.01 cases.

Assume the 30 students are b1, b2, ..., b14, g1, g2, ..., g16.

After you list the 39.01 cases we will talk further.

 

[watchkimberly]

I redid the second question.
16C3 *14C3 = (16*15*14/3*2*1)*(14*13*12/3*2*1) = 203,840

 

[watchkimberly]

Thank you for your help, I had to relook it over and I realize my mistake.