Probability

[Monds]

Let A and B be two independent events in S. It is known that P(A ∩ B) = 0.16 and P(A ∪ B) = 0.64. P(B) =

 

[pka]

Given that [imath]A \& B[/imath] be two independent events in [imath]\mathcal{S}[/imath]
That means [imath]\mathcal{P}(A \cap B)=\mathcal{P}(A )\mathcal{P}(B)[/imath]
Therefore [imath]\mathcal{P}(A \cup B)=\mathcal{P}(A )+\mathcal{P}( B)-\mathcal{P}(A \cap B)[/imath]

 

[Deleted member 4993]

Let A and B be two independent events in S. It is known that P(A ∩ B) = 0.16 and P(A ∪ B) = 0.64. P(B) =

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