Hello, deevicsm!

Jar containing 3 red, 7 green, 4 blue, 11 yellow marbles ... 25 total.

You randomly draw 2 marbles.

What is the probability of neither being yellow?

Your first answer is the probability of getting a non-yellow in

**one** draw.

Your second answer is correct.

The prob. of a non-yellow on the 1<sup>st</sup> draw: \(\displaystyle \,\frac{14}{25}\)

The prob. of a non-yellow on the 2<sup>nd</sup> draw: \(\displaystyle \,\frac{13}{24}\)

Therefore: \(\displaystyle \,P(\text{two non-yellows})\;=\;\frac{14}{25}\,\time\frac{13}{24}\;=\;\frac{91}{300}\;\approx\;30\%\)