Probability

valnadam

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Feb 7, 2011
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A man rolls an ordinary die 6 times. What is the probability that he gets at least 5 threes? Round your answer to four decimal places.I'm new at Statistics and don't know where to start with this problem. Thanks
 

pka

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valnadam said:
A man rolls an ordinary die 6 times. What is the probability that he gets at least 5 threes? Round your answer to four decimal places.I'm new at Statistics and don't know where to start with this problem. Thanks
That means either five threes or six threes.
\(\displaystyle \binom{6}{5}\left(\frac{1}{6}\right)^5\left(\frac{1}{6}\right)+\left(\frac{1}{6}\right)^6\)
 

valnadam

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Feb 7, 2011
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So do i put all thoses numers together? Looks like I have to multiply then add
 

valnadam

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I got 0.0001500
 
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