Probabiltiy: survival of swine based on what drug was given to them

[xclusive229]

I recently conducted some animal research where I was investigating survival of swine based on what drug was given to them. Data are shown below.

	Survived	Died	Totals
Drug 1	7	0	7
Drug 2	5	2	7
Totals	12	2	14

a. Let A_i represent the drug provided: A₁ is drug 1, A₂ is drug 2. Let B_i represent the pig's survival: B₁ indicates that the animal survived, and B₂ indicates that it died. For each cell in the table below, calculate the joint probability. In other words, calculate P(A₁ B₁), P(A₁ B₂), P(A₂ B₁), and P(A₂ B₂). Place these probabilities in the following table. (Don't panic here. This is as easy as you think it is.)

	Survived	Died
Drug 1	35	14
Drug 2	0	0

b. For each row and column, calculate the marginal probability. In other words, calculate the four marginal probabilities, P(A₁), P(A₂), P(B₁), and P(B₂). Place them in the next table with the results from part a. (Just remember how we calculated marginal probability in class.)

	Survived	Died	Totals
Drug 1	7/7	0/7	7/14
Drug 2	5/7	2/7	7/14
Totals	12/14	2/14	14/14

**Are these parts correct?**

 

[stapel]

I recently conducted some animal research....

Data are shown below....

(Don't panic here. This is as easy as you think it is.)....

Just remember how we calculated marginal probability in class....

**Are these parts correct?**

Are you a researcher, a teacher, or a student? About which "parts" are you asking? "Correct" how?

 

[xclusive229]

I am a student, and I am looking at (a.) & (b.) ..... I had to fill in the blanks

a. 35,14
0,0

b. 7/7,0/7,7/14
5/7,/7,7/14
12/14,2/14