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Probably right for the wrong reason: complete square for -x^2 - 12x

Seed5813

New member
Joined
Jan 29, 2018
Messages
24
1. LarCalcET6 5.8.037.

Find or evaluate the integral by completing the square:


. . . . .\(\displaystyle \displaystyle \int\, \dfrac{1}{\sqrt{\strut -x^2\, -\, 12x\,}}\, dx\)

[HR][/HR]
So when I did complete the square I did

-x^2 -12x
= -(x^2 + 12x)
= -(x^2 +12x +36) - 36
= -36 - (x + 6)^2

I didn't know what to do with the negative so I just ignored it and got the right answer but I feel like I cheated. That negative in front of the x is what F'd me up.

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lev888

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Jan 16, 2018
Messages
211
Looks like you have -36 twice instead of +36 and -36.
 

Seed5813

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Joined
Jan 29, 2018
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