MathClown007
New member
- Joined
- Aug 16, 2015
- Messages
- 8
Simplify the expression by removing all factors that are perfect squares from inside the radical.
1. Square Root is 200. Simplify.
2. Let's factor 200 -- [FONT=KaTeX_Main]2×2×5×5×2=22×52×2200, equals, 2, times, 2, times, 5, times, 5, times, 2, equals, 2, start superscript, 2, end superscript, times, 5, start superscript, 2, end superscript, times, 2[/FONT]. Therefore, [FONT=KaTeX_Main]200[FONT=KaTeX_Main]200200[/FONT] has at least one factor which is a perfect square ...
With the above formula, I can work out the answer. However, I don't get HOW they derived [/FONT]2×2×5×5×2 to find 200. Did they randomly guess numbers to come up with 200, or is there a method to find out the 200 factor? I would imagine there is. But I have no idea
how it is done. So, can someone please explain HOW to find the numbers that may (or may not) have a perfect square in them. Thank you!
1. Square Root is 200. Simplify.
2. Let's factor 200 -- [FONT=KaTeX_Main]2×2×5×5×2=22×52×2200, equals, 2, times, 2, times, 5, times, 5, times, 2, equals, 2, start superscript, 2, end superscript, times, 5, start superscript, 2, end superscript, times, 2[/FONT]. Therefore, [FONT=KaTeX_Main]200[FONT=KaTeX_Main]200200[/FONT] has at least one factor which is a perfect square ...
With the above formula, I can work out the answer. However, I don't get HOW they derived [/FONT]2×2×5×5×2 to find 200. Did they randomly guess numbers to come up with 200, or is there a method to find out the 200 factor? I would imagine there is. But I have no idea
how it is done. So, can someone please explain HOW to find the numbers that may (or may not) have a perfect square in them. Thank you!