problem with 1/2 power

[bfolson621]

2lnx(1/2) + ln(x-1) - ln2 = 0
2lnx(1/2) + lnx - ln - 2ln = 0
2lnx(1/2) +lnx - ln = 2ln
2lnx(1/2) +lnx = 3ln
2lnx(1/2) = 3ln - lnx
2lnx(1/2) = ln(3-1)
:?: [/img][/code]

 

[Deleted member 4993]

2lnx(1/2) + ln(x-1) - ln2 = 0
2lnx(1/2) + lnx - ln - 2ln = 0....does not work that way - ln is not an multiplication operation.2lnx(1/2) +lnx - ln = 2ln
2lnx(1/2) +lnx = 3ln
2lnx(1/2) = 3ln - lnx
2lnx(1/2) = ln(3-1)
:?: [/img][/code]

2lnx^(1/2) + ln(x-1) - ln2 = 0

ln[{x^(1/2)}^2] + ln(x-1) - ln2 = 0

ln[x] + ln(x-1) - ln2 = 0

ln[x*(x-1)/2] = ln(1)

Now continue...