B bucknaged New member Joined Dec 14, 2011 Messages 11 Jan 16, 2012 #1 Can someone evaluate this problem My answer just doesn't seem right. Any help is appreciated (2x^3 y1/3)^6 (z^-2/3xy^-1) 64x^18 y^2 3xy^1/z^2 (64)(3)x^19y^3/z^2= 192x^19y^3/z^2
Can someone evaluate this problem My answer just doesn't seem right. Any help is appreciated (2x^3 y1/3)^6 (z^-2/3xy^-1) 64x^18 y^2 3xy^1/z^2 (64)(3)x^19y^3/z^2= 192x^19y^3/z^2
B bucknaged New member Joined Dec 14, 2011 Messages 11 Jan 16, 2012 #2 I scanned the problem to eliminate confusion Attachments exponent 001.jpg 96.1 KB · Views: 2
D Deleted member 4993 Guest Jan 16, 2012 #3 bucknaged said: I scanned the problem to eliminate confusion Click to expand... So do you think Jeff solved your problem? If he did - which would that be?
bucknaged said: I scanned the problem to eliminate confusion Click to expand... So do you think Jeff solved your problem? If he did - which would that be?
B bucknaged New member Joined Dec 14, 2011 Messages 11 Jan 16, 2012 #4 I believe it is the second solution, in which i had it correct
D Deleted member 4993 Guest Jan 16, 2012 #5 bucknaged said: I believe it is the second solution, in which i had it correct Click to expand... Correct....
bucknaged said: I believe it is the second solution, in which i had it correct Click to expand... Correct....
B bucknaged New member Joined Dec 14, 2011 Messages 11 Jan 16, 2012 #6 Thanks for the help guys. Its greatly appreciated
