Its is given that f(x) >= e^(x-1)+lnx+x^2 for x>0 and f(1) = 2

I have to find the tangent of f in A(1,2) which is: y-f(1)=f ' (1)(x-1)

I have trouble finding f ' (1)

I tried finding it through extremum but didnt manage anything. Any help would be appreciated....