Question: Find the cordinates of the vertex and the equation of the axis of symmetry for the parabola with equation 2x^2 + 2x - y = -3
So far I got: I didn't get very far on this question because i am having problems factoring. In my book to get the coordinates and the equation of the axis of symmentry it say that you must rewrite the equation in the form (x-h)^2 = 4p(y-k). So I seperated my terms and that's where I'm stuck I have 2x^2 + 2x = y-3. but i dont kno how i would factor this out to get it in the above form could somone help thanks?!
So far I got: I didn't get very far on this question because i am having problems factoring. In my book to get the coordinates and the equation of the axis of symmentry it say that you must rewrite the equation in the form (x-h)^2 = 4p(y-k). So I seperated my terms and that's where I'm stuck I have 2x^2 + 2x = y-3. but i dont kno how i would factor this out to get it in the above form could somone help thanks?!