Problems with equations: 2x^(-200) = 0, etc

sliptop

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May 6, 2007
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I am having problems with equations:

1) \(\displaystyle 2x^{-200}=0\)


2) \(\displaystyle 3x^{6x}=0\)


3) \(\displaystyle 4x^{15x}=0\)


4) \(\displaystyle 3x^{-7x}+2=0\)

If someone could explain how to do these, that would be great. Thank you!
 
1) Divide through by 2. You then have 1/x<sup>200</sup> = 0. Can this ever be true? (If you're not sure, multiply through by x<sup>200</sup>. Is the result a valid equation?)

2) Divide through by 3. You then have x<sup>something</sup> = 0. Using what you know about powers, what then must be the value of the base?

3) This works just like (2).

4) This is quite different from the others, which are quite simple. But the first steps are still easy: Subtract the 2. Divide through by the 2. What you're left with cannot, I don't think, be solved algebraically. You'll need to use numerical methods. About all you can do, straight off, is determine the sign on x.

Eliz.
 
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