Proof: Given <BAC, <ACD supp., <CDF, <DFE supp., prove....

[loyallyroyal]

Here is the picture that comes with the problem http://img155.imageshack.us/img155/8134 ... elpur7.png

And here is a rough "drawing":

       A           B
      ,*----------* 
    ,  |        , |
C *-----------* D |
  |    |      |   |
  |   ,*------|---,
  | ,         | ,
E *-----------* F

4. Write a flow proof
Given: <BAC and <ACD are supplementary. <CDF and <DFE are supplementary.
Prove: segment AB is parallel to segment EF

<BAC and <ACD are supplementary same-side interior angles forned by transversal segment AC with segment AB and segment CD. So, <CDF and <DFE are supplementary same-side interior angles formend by transversal segment DF and segment CD and segment EF. So, segment CD is parallel to segment EF. Since segment AB and Segment EF are parallel to the same segment, they are parallel to each other.

yes its a proof but how do I make it a flow proof I dont get the whole flow proof thing and was wondering if someone could make it into one so I could know what I am doing thanks!
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edited by stapel -- reason for edit: inserting copy of pic

 

[pka]

Yes, I agrree that that works as a proof.