Faded-Maximus
New member
- Joined
- Sep 24, 2006
- Messages
- 31
Prove that if 4 is subtracted from the square of an integer greater than 3, the result is a composite number.
I have let k represent any positve integer.
therefore k + 3 > 3.
(k+3)^2 - 4
k^2 + 6k + 9 - 4
k^2 + 6k + 5
I am stuck here and don't know how to proceed. If somebody could help that would be great.
I have let k represent any positve integer.
therefore k + 3 > 3.
(k+3)^2 - 4
k^2 + 6k + 9 - 4
k^2 + 6k + 5
I am stuck here and don't know how to proceed. If somebody could help that would be great.