#### realjoejanuary

##### New member

- Joined
- Sep 22, 2022

- Messages
- 1

a( squared) = 2* b(squared)

a(squared) is an even integer

a is an even integer

Back to the original equation

a( squared) = 2*b(squared)

a(squared) / 2 = b(squared)

b(squared) = a(squared) / 2

If b(squared) = some number / 2 then

b( squared) is an even integet

so b is an even integer

Since a & b are both even integers a/b

cannot b the square root of 2. ( reducable to

some other number which will put us through same process)

YET

The proofs I've looked at go through extra steps after showing a is a multiple of some number to show b is also a multiple of some number. Isn't it enough to show that b(squared) can be derived by dividing a( squared) by 2 making b(squared) an even number?