Proofing a quadratic equation

Kevin7654

New member
Joined
Sep 20, 2020
Messages
1
i don’t really understand how to proof 5x-x^2 is the area of the cross
 

Attachments

  • 4539DCBA-DC76-41FA-8A76-A7D38CED2CEB.jpeg
    4539DCBA-DC76-41FA-8A76-A7D38CED2CEB.jpeg
    206.4 KB · Views: 8
i don’t really understand how to proof 5x-x^2 is the area of the cross
Mentally move the vertical rectangle to one end of the flag. Then that vertical area is \(2x\)
Then the area of the reaming horizontal part is \((3-x)x\)
Now \((3-x)x+2x=~?\)
 
I see two rectangles, one 3 m by x m, so area 3x square meters, the other 2 m by x m, so area 3x square meters. However, they overlap in the middle so that "x by x" region has been counted twice. We have to subtract that once to so as not to count that overlap twice: 3x+ 2x- x^2= 5x- x^2.

Another way to do this is to think of it as 5 non-overlapping regions. The flag is 3 m long. Subtracting the x m wide middle the remaining 3- x is divided into two rectangles each of length (3-x)/2 and width x so area (3-x)x/2= (3x- x^2)/2. The two rectangles, both left and right, have total area 2(3x- x^2)/2= 3x-x^2. The flag is 2 m in width. Subtracting the x m high middle the remaining 2- x is divided into two rectangles each of length (2- x)/2 and width x so area (2x- x^2)/2. The two rectangles, both above and below, have total area 2(2x- x^2)/2= 2x- x^2. Finally, the middle is "x by x" so has area x^2 meters. Adding all of those the total area of the cross is (3x- x^2)+ (2x- x^2)+ x^2= 5x- x^2.

(And the verb you want is "prove", not "proof".)
 
Top