If we have an equilateral triangle with side (t) and a square with a side (s), and their Areas are equal, How can we represent the ratio of t:s???
I have worked at it this way:
I have the Area of the square=s^2
The Area of the triangle I will get using (a*ha)/2
I have all equal sides, The h will be found out in this way:
h^2 + (t/2)^2=t^2
h= [t*3^(1/2)]/2
then when we substitute the equation Asquare=Atriangle we will have : 2s=t*3^(1/4), and therefore t:s=2:3^(1/4)
Is it correct?
I have worked at it this way:
I have the Area of the square=s^2
The Area of the triangle I will get using (a*ha)/2
I have all equal sides, The h will be found out in this way:
h^2 + (t/2)^2=t^2
h= [t*3^(1/2)]/2
then when we substitute the equation Asquare=Atriangle we will have : 2s=t*3^(1/4), and therefore t:s=2:3^(1/4)
Is it correct?