Hmmm....try m = 2lookagain said:Let m belong to the set of real numbers. Prove for m≤−0.8:
2m<m2
Let m belong to the set of real numbers. Prove for m≤−0.8:
2m<m2
f=2^m, f'=(ln2)f -> increasing on m<-0.8
g=mm, What!? g=m2
g'=3m ->What!? g' = 2m
decreasing on m<-0.8
f=g at m=-0.77 . . . No, m≈−0.77
At m =−0.77, 2m < m2.
Make the changes, don't make excuses, and move on.
** If you hadn't typed mm for m squared to begin with, I would anticipate that you would
have calculated the derivative correctly. As it is, as long as you continue to type it that way,
you're needlessly inviting error in judgment.