F frazza999 New member Joined May 25, 2014 Messages 3 May 25, 2014 #1 Hey guys struggling with the following question It would be great if i could get a bit of help. Thank you very much
Hey guys struggling with the following question It would be great if i could get a bit of help. Thank you very much
pka Elite Member Joined Jan 29, 2005 Messages 11,978 May 25, 2014 #2 frazza999 said: Hey guys struggling with the following question Click to expand... If \(\displaystyle y=\log_b(x)\) then by definition \(\displaystyle x=b^y\). So \(\displaystyle \log(x)=\log(b^y)=y\log(b)\). So \(\displaystyle y=\dfrac{\log(x)}{\log(b)}\). qed
frazza999 said: Hey guys struggling with the following question Click to expand... If \(\displaystyle y=\log_b(x)\) then by definition \(\displaystyle x=b^y\). So \(\displaystyle \log(x)=\log(b^y)=y\log(b)\). So \(\displaystyle y=\dfrac{\log(x)}{\log(b)}\). qed
