First, write an expression for L(n-1).L(n)= View attachment 20365
1) Calculate L(0): I got 2/3
2) Calculate L(1) using integration by parts: I got 4/15
3) Show that for every natural number n of (2n+3)*L(n)=2*n*L(n-1). Please help me on solving this problem. I tried using integration by parts but could not ptove this statement..
I agree with you on the first two parts. It may help if you show your work for part 2, as it is similar to what you have to do for part 3, but it will not necessarily lead you directly to the best way. What we need to see is your work on part 3, so we can either find a specific error, or suggest a different way to split into parts. You may be closer than you think!L(n)= View attachment 20365
1) Calculate L(0): I got 2/3
2) Calculate L(1) using integration by parts: I got 4/15
3) Show that for every natural number n of (2n+3)*L(n)=2*n*L(n-1). Please help me on solving this problem. I tried using integration by parts but could not ptove this statement..
That was my fault - again. I added that from his attempt to correct his response. But I did add there at the bottom as [added later].When, and how, did that work get added to the OP? That should have been a response to what we'd written, so we'd be notified of it.
But, yes, that's most of the work. Just distribute and stare at what you get.
It is clear for me now, Thanks a lot for your help!It's good, you're almost there! Distribute into the (1-x). The -x part will give you a L(n) term that you can combine to the left hand side.
Alright, Thanks a lot! That was very helpfulWhen, and how, did that work get added to the OP? That should have been a response to what we'd written, so we'd be notified of it.
But, yes, that's most of the work. Just distribute and stare at what you get.