UserKunal123
New member
- Joined
- Jul 9, 2019
- Messages
- 1
This is the question from my text book:
Show that f:R-{3}—>R defined by f(x)=(x-2)/(x-3) is not onto. This is what I have done so far:
f(x)=y=(x-2)/(x-3)
=> x=(3y-2)/(y-1)
For y=1, x is undefined.
This means for y=1 there is no pre-image x in the Domain. Hence, the function is not onto.
I doubt that the function is not onto just because for y=1, x is undefined. What have I done wrong and how do I prove that the function is not onto?
Show that f:R-{3}—>R defined by f(x)=(x-2)/(x-3) is not onto. This is what I have done so far:
f(x)=y=(x-2)/(x-3)
=> x=(3y-2)/(y-1)
For y=1, x is undefined.
This means for y=1 there is no pre-image x in the Domain. Hence, the function is not onto.
I doubt that the function is not onto just because for y=1, x is undefined. What have I done wrong and how do I prove that the function is not onto?