pythagoras' therom in Trig

[1141]

The exercise I need to do is an attachment below.
I know that the formula I need to use is cos[sup:278dabhu]2[/sup:278dabhu]? + sin[sup:278dabhu]2[/sup:278dabhu]? ? 1.
I think I may be putting the values in the wrong place in the equation, because for the first question, 1ai, don't get the correct answer of 11. Nowhere even close.

 

[Deleted member 4993]

The exercise I need to do is an attachment below.
I know that the formula I need to use is cos[sup:1z2k4edz]2[/sup:1z2k4edz]? + sin[sup:1z2k4edz]2[/sup:1z2k4edz]? ? 1.
I think I may be putting the values in the wrong place in the equation, because for the first question, 1ai, don't get the correct answer of 11. Nowhere even close.

Please show us your work - so that we know where to begin to help you.

The problem 1(a) - CANNOT have its hypoteneus = 11 - you might be looking at the answer of wrong problem or the answer is wrong.

 

[1141]

The exercise I need to do is an attachment below.
I know that the formula I need to use is cos[sup:22be9zq9]2[/sup:22be9zq9]? + sin[sup:22be9zq9]2[/sup:22be9zq9]? ? 1.
I think I may be putting the values in the wrong place in the equation, because for the first question, 1ai, don't get the correct answer of 11. Nowhere even close.

Please show us your work - so that we know where to begin to help you.

cos[sup:22be9zq9]2[/sup:22be9zq9]? + sin[sup:22be9zq9]2[/sup:22be9zq9]? ? 1
cos[sup:22be9zq9]2[/sup:22be9zq9](5?3 / x) + sin[sup:22be9zq9]2[/sup:22be9zq9](8.8 / x) ? 1
cos[sup:22be9zq9]2[/sup:22be9zq9](5?3 / x) ? 1 - sin[sup:22be9zq9]2[/sup:22be9zq9](8.8 / x)

then I became lost and didn't know what to do

 

[Deleted member 4993]

Although cos[sup:3qpakjna]2[/sup:3qpakjna]? + sin[sup:3qpakjna]2[/sup:3qpakjna]? ? 1. is derived from Pythagorean Theorem - that is not the equation to use here.

Proper equation to use - for part (i) is:

(base)[sup:3qpakjna]2[/sup:3qpakjna] + (perpendicular)[sup:3qpakjna]2[/sup:3qpakjna] = (hypotenuese)[sup:3qpakjna]2[/sup:3qpakjna] sometimes written as: b[sup:3qpakjna]2[/sup:3qpakjna] + p[sup:3qpakjna]2[/sup:3qpakjna]= h[sup:3qpakjna]2[/sup:3qpakjna]

.
.

 

[1141]

Although cos[sup:3bcxx8tw]2[/sup:3bcxx8tw]? + sin[sup:3bcxx8tw]2[/sup:3bcxx8tw]? ? 1. is derived from Pythagorean Theorem - that is not the equation to use here.

Proper equation to use - for part (i) is:

(base)[sup:3bcxx8tw]2[/sup:3bcxx8tw] + (perpendicular)[sup:3bcxx8tw]2[/sup:3bcxx8tw] = (hypotenuese)[sup:3bcxx8tw]2[/sup:3bcxx8tw] sometimes written as: b[sup:3bcxx8tw]2[/sup:3bcxx8tw] + p[sup:3bcxx8tw]2[/sup:3bcxx8tw]= h[sup:3bcxx8tw]2[/sup:3bcxx8tw]

.
.

I was going to use that formula, but then used the other one because that was what they were asking for.
Even so if I use this formula,

b[sup:3bcxx8tw]2[/sup:3bcxx8tw] + p[sup:3bcxx8tw]2[/sup:3bcxx8tw]= h[sup:3bcxx8tw]2[/sup:3bcxx8tw]
5?3[sup:3bcxx8tw]2[/sup:3bcxx8tw] + 8.8[sup:3bcxx8tw]2[/sup:3bcxx8tw] = h[sup:3bcxx8tw]2[/sup:3bcxx8tw]
15 + 77.44 = h[sup:3bcxx8tw]2[/sup:3bcxx8tw]
92.44 = h[sup:3bcxx8tw]2[/sup:3bcxx8tw]
9.6145... = h
it still doesn't give me the correct answer of 11.

 

[Deleted member 4993]

Although cos[sup:qtrc4hfd]2[/sup:qtrc4hfd]? + sin[sup:qtrc4hfd]2[/sup:qtrc4hfd]? ? 1. is derived from Pythagorean Theorem - that is not the equation to use here.

Proper equation to use - for part (i) is:

(base)[sup:qtrc4hfd]2[/sup:qtrc4hfd] + (perpendicular)[sup:qtrc4hfd]2[/sup:qtrc4hfd] = (hypotenuese)[sup:qtrc4hfd]2[/sup:qtrc4hfd] sometimes written as: b[sup:qtrc4hfd]2[/sup:qtrc4hfd] + p[sup:qtrc4hfd]2[/sup:qtrc4hfd]= h[sup:qtrc4hfd]2[/sup:qtrc4hfd]

.
.

I was going to use that formula, but then used the other one because that was what they were asking for.
Even so if I use this formula,

b[sup:qtrc4hfd]2[/sup:qtrc4hfd] + p[sup:qtrc4hfd]2[/sup:qtrc4hfd]= h[sup:qtrc4hfd]2[/sup:qtrc4hfd]
5?3[sup:qtrc4hfd]2[/sup:qtrc4hfd] + 8.8[sup:qtrc4hfd]2[/sup:qtrc4hfd] = h[sup:qtrc4hfd]2[/sup:qtrc4hfd]
15 + 77.44 = h[sup:qtrc4hfd]2[/sup:qtrc4hfd] <<< That should be 75
92.44 = h[sup:qtrc4hfd]2[/sup:qtrc4hfd]
9.6145... = h
it still doesn't give me the correct answer of 11.

You did not read my response carefully - please read it again. 11 is NOT the correct answer.

 

[1141]

b[sup:2v9nkf32]2[/sup:2v9nkf32] + p[sup:2v9nkf32]2[/sup:2v9nkf32]= h[sup:2v9nkf32]2[/sup:2v9nkf32]
5?3[sup:2v9nkf32]2[/sup:2v9nkf32] + 8.8[sup:2v9nkf32]2[/sup:2v9nkf32] = h[sup:2v9nkf32]2[/sup:2v9nkf32]
15 + 77.44 = h[sup:2v9nkf32]2[/sup:2v9nkf32] <<< That should be 75
92.44 = h[sup:2v9nkf32]2[/sup:2v9nkf32]
9.6145... = h
it still doesn't give me the correct answer of 11.

You did not read my response carefully - please read it again. 11 is NOT the correct answer.

yes, I realize I made a mistake there. That should have been in brackets.

(5?3)[sup:2v9nkf32]2[/sup:2v9nkf32] + 8.8[sup:2v9nkf32]2[/sup:2v9nkf32] = h[sup:2v9nkf32]2[/sup:2v9nkf32]
75 + 77.44 = h[sup:2v9nkf32]2[/sup:2v9nkf32]
152.44 = h[sup:2v9nkf32]2[/sup:2v9nkf32]
12.3466... = h[sup:2v9nkf32]2[/sup:2v9nkf32]
if 11 isn't the correct answer, then 12.3466... is?

 

[Denis]

If you're hesitant when using pythagorean theorem,
I don't think you're ready for these exercises and need some classroom help...

 

[mmm4444bot]

?

[ I ] used the other one because that [is] what they [are] asking for. No, they are not.

From what you posted, they specifically instruct you to use the Pythagorean Theorem.

?

152.44 = h[sup:xzdawdn2]2[/sup:xzdawdn2]

12.3466... = h[sup:xzdawdn2]2[/sup:xzdawdn2] This h^2 is a typographical error, yes?

You found h ? 12.3467, and it seems like now you're wondering whether or not this value is correct.

Check it!

Is the following equation a true statement?

[5 sqrt(3)]^2 + [8.8]^2 = [12.3467]^2

If it is, then the value is correct; however, the instructions do not ask for an approximation.

You need to report an exact form.

We assume that the given length of 8.8 is exact. Therefore, sqrt(152.44) should be acceptable.

Another exact form is: sqrt(3811)/5

(I got that by using 44/5 instead of 8.8)