Yes i got this one now. you just need to substitute t =1 to get to the answer in terms of e. The bit I was stuck on was what to do after you work out the G'(x), G''(x) . Once you get Var (X) in terms of those
Var (X)= G''(X)+G'(X)-(G'(X))^2 gives you the Variance but you have substitute the t as t=1. I dont quite know why but thats how to get the variance.
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