<<Quadratic Equation>> Finding the vertex

[element]

Hey,

I've already factored the equation and found the coordinates of the x-intercepts.
x²+6x+8=0
(x+4)(x+2)=0
x+4=0 or x+2=0
x=-4 or x=-2

Now how would I go about on finding the vertex?

Any help is appreciated, thank you!

 

[galactus]

The x coordinate of the vertex is given by \(\displaystyle \frac{-b}{2a}\)

 

[element]

Thats the axis of symetry I believe, I figured out that to. That will only give me the x coordinate of the vertex, I'm still missing the y.

 

[Unco]

If you have the x-ordinate of a point, you can find its y-ordinate by plugging that x-value into the parabola equation.

 

[element]

Got it, thank you!