A agille32 New member Joined Jun 10, 2010 Messages 3 Jun 10, 2010 #1 Write a quadratic equation having the given numbers as solutions. 3/5, -9 Is this correct? x=3/5 or x=-9 5x=3 or x+9=0 5x-3=0 or x+9=0 Quadratic equation is: (5x-3)(x+9)=0 5x^2+45x-3x-27=0 5x^2+42x-27=0
Write a quadratic equation having the given numbers as solutions. 3/5, -9 Is this correct? x=3/5 or x=-9 5x=3 or x+9=0 5x-3=0 or x+9=0 Quadratic equation is: (5x-3)(x+9)=0 5x^2+45x-3x-27=0 5x^2+42x-27=0
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,116 Jun 10, 2010 #2 agille32 said: Write a quadratic equation having the given numbers as solutions. 3/5, -9 Is this correct? x=3/5 or x=-9 5x=3 or x+9=0 5x-3=0 or x+9=0 Quadratic equation is: (5x-3)(x+9)=0 5x^2+45x-3x-27=0 5x^2+42x-27=0 Click to expand... Looks good to me! You could write many other quadratic equations with these same solutions.... If (x - a)(x - b) = 0, then c(x - a)(x - b) = c*0 So...if (5x - 3)(x + 9) = 0, then there are MANY other equivalent equations, such as 8(5x - 3)(x + 9) = 8*0
agille32 said: Write a quadratic equation having the given numbers as solutions. 3/5, -9 Is this correct? x=3/5 or x=-9 5x=3 or x+9=0 5x-3=0 or x+9=0 Quadratic equation is: (5x-3)(x+9)=0 5x^2+45x-3x-27=0 5x^2+42x-27=0 Click to expand... Looks good to me! You could write many other quadratic equations with these same solutions.... If (x - a)(x - b) = 0, then c(x - a)(x - b) = c*0 So...if (5x - 3)(x + 9) = 0, then there are MANY other equivalent equations, such as 8(5x - 3)(x + 9) = 8*0
