Good morning,
I am having difficulties with changing a quadratic equation into the standard form of f. I'm ok with factoring but I get a little confused when it comes time to completing the square. I've been doing this problem over and over but I'm not getting it still. If someone could just walk me through step by step I should be ok. Thank you to whoever reads this. Appreciate your help.
Problem:
Let f(x)=-x^2-6x+7. Determine each of the following:
a. the standard form of f
b. the vertex
c. axis of symmetry
d. x-intercepts
e. y-interecept
f. graph of (f)
Again I don't need help with a-f, just really want to focus on part a of the problem. I posted the whole thing because it was posted that it would help whoever responds to my post if they had the whole context of the problem. Thank you again!
-x^2-6x+7
-(x^2+6x-7)
(6/2)^2=9
9=(3)^2
7-9=-2
f(x)= -(x-3^2) -2 ....this is as far as I've gotten
I am having difficulties with changing a quadratic equation into the standard form of f. I'm ok with factoring but I get a little confused when it comes time to completing the square. I've been doing this problem over and over but I'm not getting it still. If someone could just walk me through step by step I should be ok. Thank you to whoever reads this. Appreciate your help.
Problem:
Let f(x)=-x^2-6x+7. Determine each of the following:
a. the standard form of f
b. the vertex
c. axis of symmetry
d. x-intercepts
e. y-interecept
f. graph of (f)
Again I don't need help with a-f, just really want to focus on part a of the problem. I posted the whole thing because it was posted that it would help whoever responds to my post if they had the whole context of the problem. Thank you again!
-x^2-6x+7
-(x^2+6x-7)
(6/2)^2=9
9=(3)^2
7-9=-2
f(x)= -(x-3^2) -2 ....this is as far as I've gotten
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