quadratic equation

[123494930w0]

9 ^ х ^ 2-х-5 + 6 ^ х ^ 2-х-4 -180 × 4 ^ х ^ 2-х-7 = 0
I really don't know how to do this. I tried: 9^x^2-x-6+6^x^2-x-6-5×4^x^2-x-6 and then :4^x^2-x-6
But it didn't work, please help me

 

[Harry_the_cat]

This is very hard to interpret. You probably need to use brackets somewhere.

 

[Steven G]

9 ^ х ^ 2-х-5 + 6 ^ х ^ 2-х-4 -180 × 4 ^ х ^ 2-х-7 = 0
I really don't know how to do this. I tried: 9^x^2-x-6+6^x^2-x-6-5×4^x^2-x-6 and then :4^x^2-x-6
But it didn't work, please help me

What you typed could be equivalent to 9^x2-x-5+6^x2-x-4 -180x4^x2-x-7=0. is this correct?

 

[HallsofIvy]

"9^x^2" might be either "\(\displaystyle 6^{x^2}\)" or \(\displaystyle (6^x)^2\) and the same for "6^x^2" and "4^x^2". The notation is ambiguous without parentheses. There is also a small "×" that might be intended to be multiplication. That should never be done in a formula using the variable x or where it might be mistaken for a variable.