M MastaLock New member Joined Dec 12, 2006 Messages 9 Dec 12, 2006 #1 5x^2 - 30x - 200 = 0 5x^2 - 30x = 200 5(x^2 - 30x) = 200 (1/2) (30) = 15 (15)^2 = 225 5(x^2 - 30 + 225) = 200 + 5(225) (x - 15)(x - 15) = (1325/5) (x - 15)^2 = 1325/5 x - 15 = Square root 265
5x^2 - 30x - 200 = 0 5x^2 - 30x = 200 5(x^2 - 30x) = 200 (1/2) (30) = 15 (15)^2 = 225 5(x^2 - 30 + 225) = 200 + 5(225) (x - 15)(x - 15) = (1325/5) (x - 15)^2 = 1325/5 x - 15 = Square root 265
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,337 Dec 12, 2006 #2 Re: Quadratic Equations Help-Am I headed in the right direct MastaLock said: 5(x^2-30x)=200 Click to expand... No good. That '30' should be a '6'.
Re: Quadratic Equations Help-Am I headed in the right direct MastaLock said: 5(x^2-30x)=200 Click to expand... No good. That '30' should be a '6'.
M MastaLock New member Joined Dec 12, 2006 Messages 9 Dec 12, 2006 #3 QE Where are you getting the 6 from???? Thank you
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,337 Dec 12, 2006 #4 No where near "heck". It's usually called the distributive property. 5(1+2) = 5*3 = 15 -- Right? 5(1+2) = 5*1+5*2 = 5+10 = 15 -- Right again. How did the 5 and the 2 get together? It works the other way, too. (15+20) = 35 -- Right? (15+20) = (5*3 + 5*4) = 5*(3+4) = 5*7 = 35 -- Right again. How did the 5 and the 4 get apart?
No where near "heck". It's usually called the distributive property. 5(1+2) = 5*3 = 15 -- Right? 5(1+2) = 5*1+5*2 = 5+10 = 15 -- Right again. How did the 5 and the 2 get together? It works the other way, too. (15+20) = 35 -- Right? (15+20) = (5*3 + 5*4) = 5*(3+4) = 5*7 = 35 -- Right again. How did the 5 and the 4 get apart?
M MastaLock New member Joined Dec 12, 2006 Messages 9 Dec 12, 2006 #5 I see where you picked up the six THANKS!!!!!!!!!!!!!!!!
D Denis Senior Member Joined Feb 17, 2004 Messages 1,706 Dec 12, 2006 #6 Masta, do yourself a favor and go here: http://www.math.unc.edu/Faculty/mccombs ... rmula.html