Y Yenessa New member Joined May 21, 2012 Messages 1 May 21, 2012 #1 how do you solve x^2+3x-5=0 using the quadratic formula?
Y yet2spark New member Joined Sep 28, 2011 Messages 22 May 21, 2012 #2 \(\displaystyle x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \ \ for\ \ ax^2+bx+c=0\) what are your a, b and c ?
\(\displaystyle x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\ \ \ for\ \ ax^2+bx+c=0\) what are your a, b and c ?
