M misscraps New member Joined Dec 5, 2008 Messages 3 Dec 6, 2008 #1 The roots of quadratic equation xsquare -(2m+4)x + (msquare+3m+2) =0 are non-zero & one root is twice the other calcuate the value of m .
The roots of quadratic equation xsquare -(2m+4)x + (msquare+3m+2) =0 are non-zero & one root is twice the other calcuate the value of m .
D Deleted member 4993 Guest Dec 6, 2008 #2 misscraps said: The roots of quadratic equation xsquare -(2m+4)x + (msquare+3m+2) =0 are non-zero & one root is twice the other calcuate the value of m . Click to expand... For a quadratic equation of the form: \(\displaystyle A\cdot x^2 \, + \, B\cdot x \, + \, C \, = \, 0\) The roots are: \(\displaystyle x_{1,2} \, = \, \frac{- \, B \, \pm \sqrt{B^2 - 4\cdot A \cdot C}}{2\cdot A}\) Please show us your work and exactly where you are stuck , so that we know where to begin to help you.
misscraps said: The roots of quadratic equation xsquare -(2m+4)x + (msquare+3m+2) =0 are non-zero & one root is twice the other calcuate the value of m . Click to expand... For a quadratic equation of the form: \(\displaystyle A\cdot x^2 \, + \, B\cdot x \, + \, C \, = \, 0\) The roots are: \(\displaystyle x_{1,2} \, = \, \frac{- \, B \, \pm \sqrt{B^2 - 4\cdot A \cdot C}}{2\cdot A}\) Please show us your work and exactly where you are stuck , so that we know where to begin to help you.
