Hi There,
I am new to this forum and wondering if anyone can help,
I have the following question. I can solve the system, and i get the right answers, but i believe the answer is false due to the word used being "or", if it was "and" it would have been correct.
B. The solution of the system
. . . . .\(\displaystyle \left. \begin{align} 2x\, -\, y\, &=\, -1 \\ y^2\, -\, x^2\, &=\, \frac{7}{4} \end{align} \right\}\)
... is\(\displaystyle \, x\, =\, \frac{1}{6}\,\) and \(\displaystyle \, y\, =\, \frac{4}{3},\, \) or \(\displaystyle \, x\, =\, -\frac{3}{2}\,\) and \(\displaystyle \, y\, =\, -2.\)
Am i correct in making this assumption? And if so, what will the "or" mean in this answer, as opposed to "and"?
I am new to this forum and wondering if anyone can help,
I have the following question. I can solve the system, and i get the right answers, but i believe the answer is false due to the word used being "or", if it was "and" it would have been correct.
B. The solution of the system
. . . . .\(\displaystyle \left. \begin{align} 2x\, -\, y\, &=\, -1 \\ y^2\, -\, x^2\, &=\, \frac{7}{4} \end{align} \right\}\)
... is\(\displaystyle \, x\, =\, \frac{1}{6}\,\) and \(\displaystyle \, y\, =\, \frac{4}{3},\, \) or \(\displaystyle \, x\, =\, -\frac{3}{2}\,\) and \(\displaystyle \, y\, =\, -2.\)
Am i correct in making this assumption? And if so, what will the "or" mean in this answer, as opposed to "and"?
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