- Thread starter hupfer
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\(\displaystyle \begin{align*}\Delta x &= \left( {\frac{{v + {v_0}}}{2}} \right)t\\{\left( {\frac{{v + {v_0}}}{2}} \right)^{ - 1}}\Delta x &= t\\\left( {\frac{2}{{v + {v_0}}}} \right)\Delta x &= t \end{align*}\)The issue I'm having is with a formula from a physics problem. I have this formula View attachment 12181

I need to rearrange like this View attachment 12182. I don't quite understand how to get there.

In this example the answer would be \(\displaystyle \frac{10x}{4}\) which can be simplified to \(\displaystyle \frac{5x}{2}\). When dividing a fraction by a number, you keep the denominator the same (in this case 4) and multiply the numerator (10) by the number on the bottom (x).Hello,

Could someone help me with a simple problem?

I would like to know how to solve a fraction within a fraction.

Example:

10/4/x

For this physics equation, you want to isolate t, so you need to divide both sides by \(\displaystyle \frac{v + v_{o}}{2}\). This will give you \(\displaystyle t = \frac{Δx}{\frac{v + v_{o}}{2}}\). Using the same technique as above, we keep the denominator the same (v + vThe issue I'm having is with a formula from a physics problem. I have this formula View attachment 12181 and I need to rearrange like this View attachment 12182. I don't quite understand how to get there.

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\(\displaystyle Δx=\left(\dfrac{v+v_0}{2}\right)t \)Hello,

Could someone help me with a simple problem?

I would like to know how to solve a fraction within a fraction.

Example:

10/4/x

The issue I'm having is with a formula from a physics problem. I have this formula View attachment 12181 and I need to rearrange like this View attachment 12182. I don't quite understand how to get there.

Multiply both sides by 2 - to get,,

\(\displaystyle 2 * Δx = (v+v_0) * t \)

can you continue?